http://stackoverflow.com/questions/605522/print-time-in-a-batch-file-milliseconds
Below batch "program" should do what you want. Please note that it outputs the data in centiseconds instead of milliseconds. The precision of the used commands is only centiseconds.
Here is an example output:
STARTTIME: 13:42:52,25
ENDTIME: 13:42:56,51
STARTTIME: 4937225 centiseconds
ENDTIME: 4937651 centiseconds
DURATION: 426 in centiseconds00:00:04,26
Here is the batch script:
@echo off
setlocal
rem The format of %TIME% is HH:MM:SS,CS for example 23:59:59,99
set STARTTIME=%TIME%
rem here begins the command you want to measure
dir /s > nul
rem here ends the command you want to measure
set ENDTIME=%TIME%
rem output as time
echo STARTTIME: %STARTTIME%
echo ENDTIME: %ENDTIME%
rem convert STARTTIME and ENDTIME to centisecondsset /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
set /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)
rem calculating the duratyion is easyset /A DURATION=%ENDTIME%-%STARTTIME%
rem we might have measured the time inbetween daysif %ENDTIME% LSS %STARTTIME% set set /A DURATION=%STARTTIME%-%ENDTIME%
rem now break the centiseconds down to hors, minutes, seconds and the remaining centisecondsset /A DURATIONH=%DURATION% / 360000
set /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
set /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
set /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)
rem some formattingif %DURATIONH% LSS 10 set DURATIONH=0%DURATIONH%
if %DURATIONM% LSS 10 set DURATIONM=0%DURATIONM%
if %DURATIONS% LSS 10 set DURATIONS=0%DURATIONS%
if %DURATIONHS% LSS 10 set DURATIONHS=0%DURATIONHS%
rem outputing
echo STARTTIME: %STARTTIME% centiseconds
echo ENDTIME: %ENDTIME% centiseconds
echo DURATION: %DURATION% in centiseconds
echo %DURATIONH%:%DURATIONM%:%DURATIONS%,%DURATIONHS%
endlocal
goto :EOF
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